| Let's figure out the structural formula for the compound shown here. |
1,4-dichloro-3-ethylhexane |
|
| The end of the name is hexane so we will start with a six-carbon-atom
chain. For convenience, let's number the chain from left to right. Numbering from right to
left would be just as correct. |
|
| Next, add an ethyl group to the third carbon in the chain. (We could
have done the chloros first, instead of the ethyl.) |
CH2CH3
|
C-C-C-C-C-C
1 2 3 4 5 6
|
|
| Next, we'll add the two chloro groups, one each to the first and fourth
carbons in the chain. For our purposes, it doesn't matter whether the chloros are put
above or below the chain. I put them below to keep them out of the way of the ethyl group.
When we get to stereoisomers of biochemicals we will have to take such orientation into
account. |
CH2CH3
|
C-C-C-C-C-C
Cl Cl
1 2 3 4 5 6
|
|
| Next, fill in the necessary hydrogen atoms to complete the molecule. In
this example I used a condensed structural formula to keep the Hs from running into the
ethyl group. A full structural formula showing a bond to each hydrogen atom could also
have been used. |
CH2CH3
|
CH2-CH2-CH-CH-CH2-CH3
|
|
Cl Cl
|
|