| Here are the the chemicals for this example: aqueous sodium iodide
solution containing I- in the bottle and molecular bromine (Br2)
dissolved in some carbon tetrachloride in the tube. |

|
| At the beginning of the reaction (left) the red Br2 is
dissolved in the nonpolar carbon tetrachloride layer at the bottom of the tube and I-
is in the water layer on top. After the reaction (right) the purple color of I2
can be seen in the nonpolar carbon tetrachloride layer at the bottom of the tube. |

|
 |
| The unbalanced equation for this reaction can be written in this way. |
Br2 + NaI I2 + NaBr |
|
| Because the sodium ions are spectator ions they can be removed from the
equation to show what is happening to the bromine and iodine. |
Br2 + I- I2 + Br- |
|
| We can dissect this equation and write separate balanced half-reactions
for the bromine and the iodine. |
Br2 + 2 e- Br- |
2 I- I2 + 2 e- |
|
| These half reactions can be added together to give the balanced equation
for this redox reaction. |
Br2 + 2 I- I2 + 2 Br- |
|
Note that in these reactions with nonmetals the change from atom to ion is reduction,
whereas with metals the change from atom to ion is oxidation. That is an important
difference between metals and nonmetals.
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E-mail instructor:
Eden Francis
Clackamas Community College
©1998, 1999 Clackamas Community College, Hal Bender