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REVIEW OF ELECTRON CONFIGURATIONS
Historically, the properties of elements and the way those elements combined with other
elements were the basis for the development of the periodic table (particularly the short
form in the latter half of the 19th century). When physicists developed an understanding
of how atoms were constructed (particularly the configuration of the electrons), it was
possible to relate that structure to the periodic table (particularly the long form). Our
next lesson (Bonding) will emphasize how the electron configurations dictate the chemical
properties and combining patterns of the elements.
| For now lets focus on how electron configurations are related to the
shape of the periodic table. To begin, I would like you to take a moment to write out the
complete electron configuration for these three elements: hydrogen, lithium and sodium.
Hydrogen has one electron. Lithium has three electrons. Sodium has eleven electrons. So
take a moment to do that, then continue with the next page. |
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ELECTRON CONFIGURATIONS AND THE PERIODIC TABLE
| These are the electron configurations you should have. Notice that
these three elements are all in group Ia of the periodic table. Notice also that each of
those electron configurations ends in s1. It is a different s1 for
each element--it is 1s1 for hydrogen, 2s1 for lithium, and 3s1
for sodium--but notice the similarity in that they all end in s1. |
| H |
1 |
1s1 |
| Li |
3 |
1s22s1 |
| Na |
11 |
1s22s22p63s1 |
|
Now take a look at the periodic table shown below. (A similar table is shown in example
2 in your workbook.) It is another periodic table, but instead of having atomic weights it
has the last part of the electron configuration for each of the elements.
| Periodic Table with Partial Electron
Configurations |
H
1s1 |
|
He
1s2 |
Li
2s1 |
Be
2s2 |
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B
2s22p1 |
C
2s22p2 |
N
2s22p3 |
O
2s22p4 |
F
2s22p5 |
Ne
2s22p6 |
Na
3s1 |
Mg
3s2 |
Al
3s23p1 |
Si
3s23p2 |
P
3s23p3 |
S
3s23p4 |
Cl
3s23p5 |
Ar
3s23p6 |
K
4s1 |
Ca
4s2 |
Sc
4s23d1 |
Ti
4s23d2 |
V
4s23d3 |
Cr
4s13d5 |
Mn
4s23d5 |
Fe
4s23d6 |
Co
4s23d7 |
Ni
4s23d8 |
Cu
4s13d10 |
Zn
4s23d10 |
Ga
4s24p1 |
Ge
4s24p2 |
As
4s24p3 |
Se
4s24p4 |
Br
4s24p5 |
Kr
4s24p6 |
Rb
5s1 |
Sr
5s2 |
Y
5s24d1 |
Zr
5s24d2 |
Nb
5s14d4 |
Mo
5s14d5 |
Tc
5s24d5 |
Ru
5s14d7 |
Rh
5s14d8 |
Pd
4d10 |
Ag
5s14d10 |
Cd
5s24d10 |
In
5s25p1 |
Sn
5s25p2 |
Sb
5s25p3 |
Te
5s25p4 |
I
5s25p5 |
Xe
5s25p6 |
Cs
6s1 |
Ba
6s2 |
La*
6s25d1 |
Hf
6s25d2 |
Ta
6s25d3 |
W
6s25d4 |
Re
6s25d5 |
Os
6s25d6 |
Ir
6s25d7 |
Pt
6s15d9 |
Au
6s15d10 |
Hg
6s25d10 |
Tl
6s26p1 |
Pb
6s26p2 |
Bi
6s26p3 |
Po
6s26p4 |
At
6s26p5 |
Rn
6s26p6 |
Fr
7s1 |
Ra
7s2 |
Ac§
7s26d1 |
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* |
Ce |
Pr |
Nd |
Pm |
Sm |
Eu |
Gd |
Tb |
Dy |
Ho |
Er |
Tm |
Yb |
Lu |
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| § |
Th |
Pa |
U |
Np |
Pu |
Am |
Cm |
Bk |
Cf |
Es |
Fm |
Md |
No |
Lr |
| Specifically, take a look at hydrogen, lithium, sodium and potassium and
you will see that that similarity continues on down the periodic table. All of the
elements in group Ia end in s1 for their electron configuration. What is
different about them is which s1 they end with. Notice also that this
periodic table only shows the last part of the electron configuration. The reason for this
is that the chemical properties of an element are determined by the outermost electron
structure. So this periodic table was prepared with just those outermost electron
configurations written on it. |
| Ia |
| H 1s1 |
| Li 2s1 |
| Na 3s1 |
| K 4s1 |
| Rb 5s1 |
| Cs 6s1 |
| Fr 7s1 |
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| Now look at group IIa, all of them end in s2 but a different s2
for each one: 2s2 for beryllium, 3s2 for magnesium, and so on. Next,
what comes after the s sublevel is filled? If we go one electron past magnesium, we get
aluminum. Its outermost electron configuration is 3s23p1. Notice
that if you look above and below aluminum, all of the outermost electron configurations
for this group of elements have the same pattern. What is different is which period they
are in. Boron is 2s22p1. Aluminum is 3s23p1.
Gallium is Ga and is an element you didn't have to memorize, but from its position on the
periodic table, you can see that it is 4s24p1. And so on, on down. |
| IIa |
IIIa |
| Be 2s2 |
B 2s22p1 |
| Mg 3s2 |
Al 3s23p1 |
| Ca 4s2 |
Ga 4s24p1 |
| Sr 5s2 |
In 5s25p1 |
| Ba 6s2 |
Tl 6s26p1 |
| Ra 7s2 |
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| If you keep going to the right on the periodic table, notice how with each
column there is one more p electron in each of the energy levels, right over to the inert
gases. |
B
2s22p1 |
C
2s22p2 |
N
2s22p3 |
O
2s22p4 |
F
2s22p5 |
Ne
2s22p6 |
Al
3s23p1 |
Si
3s23p2 |
P
3s23p3 |
S
3s23p4 |
Cl
3s23p5 |
Ar
3s23p6 |
Ga
4s24p1 |
Ge
4s24p2 |
As
4s24p3 |
Se
4s24p4 |
Br
4s24p5 |
Kr
4s24p6 |
In
5s25p1 |
Sn
5s25p2 |
Sb
5s25p3 |
Te
5s25p4 |
I
5s25p5 |
Xe
5s25p6 |
Tl
6s26p1 |
Pb
6s26p2 |
Bi
6s26p3 |
Po
6s26p4 |
At
6s26p5 |
Rn
6s26p6 |
|
| Notice that when you deal with the transition metals, the pattern is not
quite so distinct. |
Sc
4s23d1 |
Ti
4s23d2 |
V
4s23d3 |
Cr
4s13d5 |
Mn
4s23d5 |
Fe
4s23d6 |
Co
4s23d7 |
Ni
4s23d8 |
Cu
4s13d10 |
Zn
4s23d10 |
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| There are patterns here but the patterns are not as reliable. Let's start
with element number 21, scandium. From calcium to scandium, the additional electron goes
into the 3d1. So scandium has 4s23d1, or if you prefer,
3d14s2, as shown in example 2 in your workbook. You can write it in
either direction, but it is 4s2 and 3d1. Then the next electron (the
22nd one) also goes in the 3d sublevel . Thus titanium, Ti, has 3d2 as part of
its electron configuration. Vanadium, then, is 3d3 and so on across except that
you will notice that chromium does not have 3d4 like you might expect. We
continue with manganese at 3d5 and 4s2 and continue across with 3d6,
3d7, 3d8 but copper is not 3d9. You will not be expected
to know what the exact electron configuration is for the transition elements when they
alter that configuration a little bit. So when you are asked to figure out the electron
configuration for a transition element, it probably will be one that follows the pattern,
rather than one that doesn't. |
PATTERNS
The point here is to emphasize some of the patterns that exist in the relationship
between the electron configurations of the elements and the location of the elements on
the periodic table and even the shape of the periodic table.
Looking at this example note how the periodic table can be broken up into s, p, d and f
blocks. The first two columns of the periodic table (groups Ia and IIa) are in the s block
because the elements in these two groups have their outermost electrons in s orbitals.
Note that the s block has two groups because atoms can put two electrons in an s sublevel.
| s1 |
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s2 |
| s1 |
s2 |
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p1 |
p2 |
p3 |
p4 |
p5 |
p6 |
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d1 |
d2 |
d3 |
(d4) |
d5 |
d6 |
d7 |
d8 |
(d9) |
d10 |
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f1 |
(f2) |
f3 |
f4 |
f5 |
f6 |
f7 |
(f8) |
f9 |
f10 |
f11 |
f12 |
f13 |
f14 |
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The p block consists of groups IIIa through the inert gases. These are the elements
which have their last electrons in p orbitals. Note that there are six groups in this
block because atoms can put up to six electrons into a p sublevel.
The transition elements comprise the d block. The d block has 10 columns because up to
10 electrons will fit into a d sublevel.
The f block at the bottom of the periodic table has 14 columns because up to 14
electrons can fit into an f sublevel.
Remember the pattern we worked with that resulted in the electron configurations. 1s,
then 2s, 2p, 3s, then 3p, 4s, then 3d, 4p, 5s. That resulted in electron configurations
that looked like this. 1s2, 2s2, 2p6, 3s2, 3p6,
4s2, 3d10 and so on. The periodic table shows that same arrangement
in a different way. The first period has 1s1 then 2. The second
period has 2s1 then 2, then 2p1, 2, 3,
4, 5, and 6. Similarly, the third period has 3s1
then 2, then 3p1, 2, 3, 4, 5
and 6. The fourth period with the transition elements in the middle has 4s1
then 2, followed by 3d1, 2, 3, 4 is
altered, then 5, 6, 7, 8, 9 is also
altered, then 10, followed by 4p1, 2, 3, 4,
5 and 6. The periodic table continues on showing the pattern
dictated by the electron configurations.
SHORT CUTS FOR ELECTRON CONFIGURATIONS
Next, let's use the periodic table to provide a short cut method of getting the last
part of the electron configuration for nearly any element.
| Let's take calcium, element number 20, as our first example. It is in the
fourth period and in the s block, so its electron configuration will end with 4s. Calcium
is in the second column of the s block, so it has two electrons in that sublevel and the
outermost electron configuration is 4s2. |
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| Iron, element number 26, is also in the fourth period but it is in the d
block. You need to remember that 3d gets electrons after 4s. Because iron is
in the sixth spot of the d block, the last electron in the configuration is 3d6.
The s electrons are also important to the chemistry of the transition metals so they are
usually included as outermost electrons. Therefore the electron configuration ends with 4s23d6
(or alternately 3d64s2). |
Fourth
Period |
3d1 |
3d2 |
3d3 |
3d4 |
3d5 |
26
Fe
4s23d6 |
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| For elements in the p block, count down the periods to get the energy
level of the last electrons and count over from the edge of the p block to determine how
many electrons are in the last sublevel. For example, nitrogen is in the second period and
is the third element over in the p block, so its electron configuration ends with 2p3.
If you are figuring the electron configuration for the purpose of determining the number
of valence electrons, be sure to include electrons in the s sublevel. For nitrogen
that would be 2s22p3 for a total of 5 valence electrons. |
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| Another example is iodine, element number 53. It is in the fifth period
and it is the fifth element over in the p block, so its electron configuration ends with
5p5. Again, if our concern is valence electrons we would include the s
sublevel, 5s25p5. |
Fifth
Period |
5p1 |
5p2 |
5p3 |
5p4 |
53
I
5s25p5 |
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PRACTICE
For practice, try figuring out the last orbital electron configuration for the elements
shown below (they are also listed in example 4 in your workbook). Use the periodic table
in workbook example 1 for reference. Then use the periodic table in workbook example 2 to
check your answers. That table includes the s electrons for the p block and d block
elements. You may include them or not as you wish.
SHORT CUTS AND COMPLETE CONFIGURATIONS
This short-cut method can also be used to determine the complete electron
configurations. Use the location of the element on the periodic table to figure out the
last entry in the configuration, as you have just done. Use the shape of the periodic
table to remind you of the order in which the sublevels fill. Do this by reading the
blocks in each period in order. First 1s. Then 2s, 2p. Then 3s, 3p. Then 4s, 3d, 4p. Next
5s, 4d, 5p, and so on. Keep adding electrons to that pattern until you have reached what
you know to be the end of the electron configuration for that element based on its
location on the periodic table.
| 1s |
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1s |
| 2s |
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2p |
| 3s |
3p |
| 4s |
3d |
4p |
| 5s |
4d |
5p |
| 6s |
* |
5d |
6p |
| 7s |
§ |
6d |
7p |
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*
§ |
4f |
|
| 5f |
ORBITALS AND THE PERIODIC TABLE
| The repeating nature of the electron configuration or electron structure
is shown here also, this time with emphasis on the orbitals. Note that the atomic size
trends are also apparent in this diagram. |
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| If you take a look at the electron configurations that are shown there,
hydrogen with its 1s1 shows the 1s orbital. Then for helium, 1s2,
the 1s orbital is also shown. It is a little bit darker to indicate that there are two
electrons in it. |
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| Then the third electron goes into the 2s1 and this is shown
with lithium. Notice that the 1s orbital is shown in the center and then the 2s orbital is
shown around it in the lighter color and larger. With beryllium there are two electrons in
the 2s orbital. |
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| With boron if you look closely, you can see the p orbital that has the
fifth electron in it. With carbon you can see that there are two of the p orbitals. With
nitrogen you can see that there are three of the p orbitals shown. With oxygen there are
still the same number of orbitals, but there are four p electrons. There are more and more
electrons as you go from oxygen to fluorine to neon. Thus the diagrams get darker to show
the higher concentration of electrons. |
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| Then with sodium you have to start working with another s orbital and that
is shown in yellow here. Magnesium shows another electron in that s orbital. |
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| With aluminum, silicon, and phosphorus, you can see the additional p
orbitals in the third energy level showing up there. Then the concentration of electrons
gets more intense and thus the color gets darker and you go to sulfur, chlorine, and
argon. |
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| Again with one more electron after argon, you need to start another energy
level and that is shown as the 4s energy sublevel with potassium and also the same with
calcium. |
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This particular progression of elements leaves off after Ca because that is where you
start getting into the "d" orbitals which become much more difficult to draw. So
with this diagram you can see the progression of additional electrons resulting in
additional orbitals and also the orientation and build-up of the orbitals that are being
used. You can also see how that relates to the arrangement of the periodic table.
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